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[Dave T.]

Hi all,

Does anyone have any tricks to allow a folder to be opened (that contains spaces) with the os.Path.dirOpen method on a Windows client ?

Cheers

Dave

[william s.]

Hi all,

Does anyone have any tricks to allow a folder to be opened (that contains spaces) with the os.Path.dirOpen method on a Windows client ?

Cheers

Dave

To open a folder with spaces using the os.Path.dirOpen function on a Windows client, wrap the folder path in double quotes. This ensures that the entire path is handled as a single item, with the spaces not construed as separators.

For instance, if the folder location is "C:\Program Files", you can open it with the following code:

import os

folder_path = 'C:\\Program Files'
os.startfile('"{}"'.format(folder_path))

This will open the folder without any problems due to gaps in the path.

[wilkinson w.]

To open a folder with spaces using the os.Path.dirOpen function on a Windows client, wrap the folder path in double quotes. This ensures that the entire path is handled as a single item, with the spaces not construed as separators.

For instance, if the folder location is "C:\Program Files", you can open it with the following code:

import os basketball stars

folder_path = 'C:\\Program Files'
os.startfile('"{}"'.format(folder_path))

This will open the folder without any problems due to gaps in the path.

This is an excellent response, and I am quite appreciative of the fact that you choose to provide it.

[Victor G.]

Hi all,

Does anyone have any tricks to allow a folder to be opened (that contains spaces) with the os.Path.dirOpen method on a Windows client ?

Cheers

Dave

To open a folder with spaces using the os.Path.dirOpen function on a Windows client, wrap the folder path in double quotes. This ensures that the entire path is handled as a single item, with the spaces not construed as separators.
phrazle
For instance, if the folder location is "C:\Program Files", you can open it with the following code:

import os

folder_path = 'C:\\Program Files'
os.startfile('"{}"'.format(folder_path))

This will open the folder without any problems due to gaps in the path.

I will try, thanks.